Crackme练习8-11题（Andrénalin）爆破记录

上将无双 发表于 2020-2-18 08:30

本帖最后由上将无双于 2020-2-18 08:34 编辑

Crackme练习8-11题（Andrénalin）爆破记录
新人刚入门破解第一次做记录；只会爆破请大神包涵
链接：https://www.52pojie.cn/thread-709699-1-1.html选用的是008-011的Andrénalin系列。
1.初步观察：程序共同点and不同点
共同点：无壳，使用VB5编写
不同点：1号、3号只有注册码框、确定键
            2号有用户名、密码、确定键

            4号只有注册码，但有小键盘而没有确定键，注册状态在右侧显示
2.选用工具
吾爱破解ollydbg
吾爱破解虚拟机
3.破解实践3.1.Andrénalin.1.exe爆破

思路：可尝试寻找判断注册码错误的指令进行修改，跳过判断直接正确
首先把程序拖入OD加载加载完后 F9运行
如图所示尝试输入伪码111 单击OK键此时弹出错误窗口

不关闭窗口切回OD 暂停运行然后Alt+K调出调用堆栈窗口

除rtcmsgbox外的堆栈都过大明显不是要找的
推测rtamsgbox是判断正误的关键处右键显示调用
上下浏览代码可知 00401E85是错误窗口的信息
尝试寻找跳转至该地址的指令
00401D88 .47          inc edi00401D89 .F7DF       neg edi
00401D8B .FF15 5C314000 call dword ptr ds:[<&MSVBVM50>;msvbvm50.__vbaFreeStr
00401D91 .8D4D D4    lea ecx,dword ptr ss:[ebp-0x2>
00401D94 .FF15 60314000 call dword ptr ds:[<&MSVBVM50>;msvbvm50.__vbaFreeObj
00401D9A .66:3BFE    cmp di,si
00401D9D    0F84 A0000000 je Andréna.00401E43          //可疑跳转
00401DA3 .FF15 2C314000 call dword ptr ds:[<&MSVBVM50>;msvbvm50.rtcBeep
00401DA9 .8B3D 48314000 mov edi,dword ptr ds:[<&MSVBV>;msvbvm50.__vbaVarDup
00401DAF .B9 04000280 mov ecx,0x80020004
00401DB4 .894D 9C    mov dword ptr ss:,e>
00401DB7 .B8 0A000000 mov eax,0xA
00401DBC .894D AC    mov dword ptr ss:,e>
00401DBF .BB 08000000 mov ebx,0x8
00401DC4 .8D95 74FFFFFF lea edx,dword ptr ss:[ebp-0x8>
00401DCA .8D4D B4    lea ecx,dword ptr ss:[ebp-0x4>
00401DCD .8945 94    mov dword ptr ss:,e>
00401DD0 .8945 A4    mov dword ptr ss:,e>
00401DD3 .C785 7CFFFFFF>mov dword ptr ss:,A>;UNICODE "SuCCESFul !"/成功信息
00401DDD .899D 74FFFFFF mov dword ptr ss:,e>
00401DE3 .FFD7       call edi                   ;<&MSVBVM50.__vbaVarDup>
00401DE5 .8D55 84    lea edx,dword ptr ss:[ebp-0x7>
00401DE8 .8D4D C4    lea ecx,dword ptr ss:[ebp-0x3>
00401DEB .C745 8C 701A4>mov dword ptr ss:,A>;UNICODE "RiCHtiG ! ...nun weiter zu CrackMe 2 !"
00401DF2 .895D 84    mov dword ptr ss:,e>
00401DF5 .FFD7       call edi
00401DF7 .8D55 94    lea edx,dword ptr ss:[ebp-0x6>
00401DFA .8D45 A4    lea eax,dword ptr ss:[ebp-0x5>
00401DFD .52          push edx                   ;ntdll.KiFastSystemCallRet
00401DFE .8D4D B4    lea ecx,dword ptr ss:[ebp-0x4>
00401E01 .50          push eax
00401E02 .51          push ecx
00401E03 .8D55 C4    lea edx,dword ptr ss:[ebp-0x3>
00401E06 .6A 30       push 0x30
00401E08 .52          push edx                   ;ntdll.KiFastSystemCallRet
00401E09 .FF15 F0304000 call dword ptr ds:[<&MSVBVM50>;msvbvm50.rtcMsgBox
00401E0F .8D95 44FFFFFF lea edx,dword ptr ss:[ebp-0xB>
00401E15 .8D4D DC    lea ecx,dword ptr ss:[ebp-0x2>
00401E18 .8985 4CFFFFFF mov dword ptr ss:,e>
00401E1E .C785 44FFFFFF>mov dword ptr ss:,0>
00401E28 .FF15 D0304000 call dword ptr ds:[<&MSVBVM50>;msvbvm50.__vbaVarMove
00401E2E .8D45 94    lea eax,dword ptr ss:[ebp-0x6>
00401E31 .8D4D A4    lea ecx,dword ptr ss:[ebp-0x5>
00401E34 .50          push eax
00401E35 .8D55 B4    lea edx,dword ptr ss:[ebp-0x4>
00401E38 .51          push ecx
00401E39 .8D45 C4    lea eax,dword ptr ss:[ebp-0x3>
00401E3C .52          push edx                   ;ntdll.KiFastSystemCallRet
00401E3D .50          push eax
00401E3E .E9 95000000 jmp Andréna.00401ED8
00401E43 >8B3D 48314000 mov edi,dword ptr ds:[<&MSVBV>;msvbvm50.__vbaVarDup
00401E49 .B9 04000280 mov ecx,0x80020004
00401E4E .894D 9C    mov dword ptr ss:,e>
00401E51 .B8 0A000000 mov eax,0xA
00401E56 .894D AC    mov dword ptr ss:,e>
00401E59 .BB 08000000 mov ebx,0x8
00401E5E .8D95 74FFFFFF lea edx,dword ptr ss:[ebp-0x8>
00401E64 .8D4D B4    lea ecx,dword ptr ss:[ebp-0x4>
00401E67 .8945 94    mov dword ptr ss:,e>
00401E6A .8945 A4    mov dword ptr ss:,e>
00401E6D .C785 7CFFFFFF>mov dword ptr ss:,A>;UNICODE "leider NeiN !"
00401E77 .899D 74FFFFFF mov dword ptr ss:,e>
00401E7D .FFD7       call edi                   ;<&MSVBVM50.__vbaVarDup>
00401E7F .8D55 84    lea edx,dword ptr ss:[ebp-0x7>
00401E82 .8D4D C4    lea ecx,dword ptr ss:[ebp-0x3>
00401E85 .C745 8C E01A4>mov dword ptr ss:,A>;UNICODE "Leider Falsch !Schau noch mal genau nach ..."
00401E8C .895D 84    mov dword ptr ss:,e>
00401E8F .FFD7       call edi
00401E91 .8D4D 94    lea ecx,dword ptr ss:[ebp-0x6>
00401E94 .8D55 A4    lea edx,dword ptr ss:[ebp-0x5>
00401E97 .51          push ecx
00401E98 .8D45 B4    lea eax,dword ptr ss:[ebp-0x4>
00401E9B .52          push edx                   ;ntdll.KiFastSystemCallRet
00401E9C .50          push eax
00401E9D .8D4D C4    lea ecx,dword ptr ss:[ebp-0x3>
00401EA0 .6A 10       push 0x10
00401EA2 .51          push ecx
00401EA3 .FF15 F0304000 call dword ptr ds:[<&MSVBVM50>;msvbvm50.rtcMsgBox
发现：当注册码错误时，00401D9D处指令实现跳转，跳过成功信息
接下来，就把该句nop掉
应该成功了，再次F9运行，输入111

至此爆破成功。
3.2.Andrénalin.2.exe Andrénalin.3.exe爆破
思路都同3.1，因为目的是跳过判断，有没有用户名的检验无所谓
操作大同小异，不多赘述
二号爆破成功：
三号爆破成功：

3.3.Andrénalin.4.exe爆破

思路：没有确定键，该如何操作呢？不如直接搜索字符串，找找注册成功的语句，然后试着强制成功注册
右键中文搜索引擎智能搜索
一大堆数字看上去让人眼花
肯定不会是加密的注册码，太长了
但是下面的registriert(德语”注册“)是关键点
出现反复的registriert信息，推测是比较验证注册码每一位的正误
随意调用其中一个地址
0040B72D >8D45 CC    lea eax,dword ptr ss:[ebp-0x3>0040B730 .8D8D 4CFFFFFF lea ecx,dword ptr ss:[ebp-0xB>
0040B736 .50          push eax                   ; /var18 = NULL
0040B737 .51          push ecx                   ; |var28 = 0012FFB0
0040B738 .C785 54FFFFFF>mov dword ptr ss:,A>; |0817E747D7A7D7C7F82836D74747A7F7E7G7C7D826D817E7B7C
0040B742 .C785 4CFFFFFF>mov dword ptr ss:,0>; |
0040B74C .FF15 5C104000 call dword ptr ds:[<&MSVBVM60>; \__vbaVarTstEq
0040B752 .66:85C0    test ax,ax
0040B755 .74 4C       je short Andréna.0040B7A3    //可疑跳转
0040B757 .8B45 08    mov eax,dword ptr ss:[ebp+0x8>;Andréna.<ModuleEntryPoint>
0040B75A .50          push eax
0040B75B .8B10       mov edx,dword ptr ds:
0040B75D .FF92 38030000 call dword ptr ds:
0040B763 .50          push eax
0040B764 .8D45 AC    lea eax,dword ptr ss:[ebp-0x5>
0040B767 .50          push eax
0040B768 .FF15 3C104000 call dword ptr ds:[<&MSVBVM60>;msvbvm60.__vbaObjSet
0040B76E .8B08       mov ecx,dword ptr ds:
0040B770 .68 BC1E4000 push Andréna.00401EBC       ;REGISTRIERT //成功注册信息
0040B775 .50          push eax
0040B776 .8985 30FFFFFF mov dword ptr ss:,e>
0040B77C .FF51 54    call dword ptr ds:

0040B77F .85C0       test eax,eax
0040B781 .DBE2       fclex
0040B783 .7D 15       jge short Andréna.0040B79A
0040B785 .8B95 30FFFFFF mov edx,dword ptr ss:[ebp-0xD>
0040B78B .6A 54       push 0x54
0040B78D .68 D41E4000 push Andréna.00401ED4
0040B792 .52          push edx                   ;ntdll.KiFastSystemCallRet
0040B793 .50          push eax
0040B794 .FF15 2C104000 call dword ptr ds:[<&MSVBVM60>;msvbvm60.__vbaHresultCheckObj
0040B79A >8D4D AC    lea ecx,dword ptr ss:[ebp-0x5>
0040B79D .FF15 D4104000 call dword ptr ds:[<&MSVBVM60>;msvbvm60.__vbaFreeObj

发现一个跳转指令跳过0040B770
尝试nop掉

运行发现已成功注册（我不知道为啥跳过一个就能成功)

4.结束语

没什么技术含量啊（基本连猜带蒙）给小白们提供一个经验参考
我做的爆破记录可能有不清楚的地方，请留言评分指正
Thanks for Reading!

2020.2.18

111234jgf 发表于 2020-2-18 13:43

感谢分享。

05586565316 发表于 2020-2-18 15:45

感谢分享

arialyy 发表于 2020-2-18 18:16

学习学习，大佬牛逼

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Crackme练习8-11题（Andrénalin）爆破记录