看不懂这个类

163585580 发表于 2022-4-19 10:05

哪位大佬能帮忙看一下这个类（如下代码）是干什么的么？已知的是service类（如下图）要继承它

//
// Source code recreated from a .class file by IntelliJ IDEA
// (powered by FernFlower decompiler)
//

package com.daowen.ssm.simplecrud;

import java.lang.reflect.ParameterizedType;
import java.lang.reflect.Type;
import java.text.MessageFormat;
import java.util.HashMap;
import java.util.List;
import org.springframework.beans.factory.annotation.Autowired;

public class SimpleBizservice<MapperClass extends SimpleMapper> implements Bizservice<MapperClass> {
@Autowired
private MapperClass mapper = null;

public SimpleBizservice() {
}

public MapperClass getMapper() {
   return this.mapper;
}

public List getEntity() {
   return this.mapper.getAllEntity();
}

public <T> T save(T t) {
   Class<?>[] funIntf = this.mapper.getClass().getInterfaces();
   Class<?> mapperClazz = null;
   if (funIntf != null && funIntf.length > 0) {
         mapperClazz = funIntf;
   }

   Class<?> clz = this.getEntityClass(mapperClazz);
   if (clz != null && !clz.isInstance(t)) {
         System.out.println("不是实体类");
         return null;
   } else {
         this.mapper.save(t);
         return t;
   }
}

public List getPageEntitys(String where, int pageIndex, int pageSize) {
   return this.mapper.getPageEntitys(where, pageIndex, pageSize);
}

public int getRecordCount(String where) {
   return this.mapper.getRecordCount(where);
}

public List getEntity(String where) {
   return this.mapper.getEntitys(where);
}

public <T> List<T> getTopEntity(String where, int topCount) {
   return this.mapper.getTopEntity(where, topCount);
}

private Class<?> getEntityClass(Class<?> mapperClass) {
   Type[] types = mapperClass.getGenericInterfaces();
   Class<?> entityClass = null;
   Type[] var4 = types;
   int var5 = types.length;

   for(int var6 = 0; var6 < var5; ++var6) {
         Type type = var4;
         if (type instanceof ParameterizedType) {
            ParameterizedType t = (ParameterizedType)type;
            if (t.getRawType() == SimpleMapper.class) {
               entityClass = (Class)t.getActualTypeArguments();
               break;
            }
         }
   }

   return entityClass;
}

public <T> int update(T t) {
   return this.mapper.update(t);
}

public int delete(String where) {
   return this.mapper.delete(where);
}

public Boolean isExist(String where) {
   return this.getRecordCount(where) > 0;
}

public <T> T load(int id) {
   Class<?>[] funIntf = this.mapper.getClass().getInterfaces();
   Class<?> mapperClazz = null;
   if (funIntf != null && funIntf.length > 0) {
         mapperClazz = funIntf;
   }

   Class<?> entityClzz = this.getEntityClass(mapperClazz);
   TableMetadata tm = TableMetadata.forClass(entityClzz);
   String where = MessageFormat.format("where{0}={1}", tm.getPkColumn(), id);
   List list = this.getEntity(where);
   return list == null ? null : list.get(0);
}

public <T> T load(String where) {
   List<T> list = this.mapper.getEntitys(where);
   return list != null && list.size() != 0 ? list.get(0) : null;
}

public <T> List<T> query(String nativateSql) {
   return this.mapper.query(nativateSql);
}

public List<HashMap<String, Object>> queryToMap(String nativateSql) {
   return this.mapper.queryToMap(nativateSql);
}

public int executeUpdate(String sql) {
   return this.mapper.nativeUpdate(sql);
}
}

w1066602520 发表于 2022-4-19 10:31

看不懂啊

lhlking 发表于 2022-4-19 10:35

凭我小学的拼音水平，感觉像是什么会员之类的

若无zz 发表于 2022-4-19 10:40

就是一个扩展的Service可以理解为是个有一堆基础方法的基类, 单表CRUD操作都包含,减少开发工作量

icysky0605 发表于 2022-4-19 10:42

这不就是个框架中的数据操作类喽，已经集成了几个常用的对象操作功能，更新，删除，判断存在等，有啥不明白的？

若无zz 发表于 2022-4-19 10:42

lhlking 发表于 2022-4-19 10:35
凭我小学的拼音水平，感觉像是什么会员之类的

以我幼儿园的拼音水平，感觉我也没必要上小学了{:301_997:}

157239486 发表于 2022-4-19 10:42

这个是mvc架构里的servcie层，调用数据库的，mapper就是对应数据库的操作，至于具体的业务逻辑你得自己知道。

du2009 发表于 2022-4-19 11:07

直接引用应该就可以。

xiadongming 发表于 2022-4-19 22:01

页: [1]

吾爱破解 - 52pojie.cn's Archiver

看不懂这个类