用网页打开php登陆页面不提示登陆是否成功

晚风811 发表于 2023-11-29 21:12

用echo输出登陆成功或者失败的提示,但是打开网页登陆的时候点击登陆没有反应.
<?php
include_once 'init.php';

if($_POST['sub']){

$username=filterstr($_POST['username']);
$password=md5(filterstr($_POST['password']));
$result=$conn->query("select * from users where username='$username' and password='$password'");
if($result->num_rows>0){
   $row=$result->fetch_assoc();
   if ($row['password']==$password){
         echo "登录成功";
   }else{
         echo "账号或密码错误";
   }
}else{
   echo "登录失败";
}
}

?>
<html>
<head>
<title>管理员登录</title>
<style>
   .login{
         width: 400px;
         margin: 0px auto;
   }
</style>
</head>
<body>
<div class="login">
<form>
   <table>
         <tr><td><lable for="username">用户</lable></td><td><input type="text" name="username" id="username"></td></tr>
         <tr><td><lable for="password">密码</lable></td><td><input type="password" name="password" id="password"></td></tr>
         <tr><td colspan="2"><input type="submit" value="登录" name="sub"></td></tr>
   </table>
</form>
</div>
</body>
</html>

dleo 发表于 2023-11-29 23:59

form的method要标明是post才能拿到提交的内容吧

shipon 发表于 2023-11-30 00:02

本帖最后由 shipon 于 2023-11-30 00:08 编辑

include_once 'init.php';
if ($_POST['sub']) {
$username = filterstr($_POST['username']);
$password = md5(filterstr($_POST['password']));
$result = $conn->query("select * from users where username='$username' and password='$password'");
if ($result->num_rows > 0) {
   $row = $result->fetch_assoc();
   if ($row['password'] == $password) {
         echo "登录成功";
   } else {
         echo "账号或密码错误";
   }
} else {
   echo "登录失败";
}
}
?>

<html>
<head>
<title>管理员登录</title>
<style>
   .login {
         width: 400px;
         margin: 0px auto;
   }
</style>
</head>
<body>
<div class="login">
<form method="POST">
   <table>
         <tr>
            <td><label for="username">用户</label></td>
            <td><input type="text" name="username" id="username"></td>
         </tr>
         <tr>
            <td><label for="password">密码</label></td>
            <td><input type="password" name="password" id="password"></td>
         </tr>
         <tr>
            <td colspan="2"><input type="submit" value="登录" name="sub"></td>
         </tr>
   </table>
</form>
</div>
</body></html>

Maiz1888 发表于 2023-11-30 09:29

不会写的话建议看下别人开源的怎么写的登录，别自己瞎琢磨，不行网上搜搜也行。你的form的action去哪了

Do_zh 发表于 2023-11-30 09:50

form表单是不是要表明post方式请求你才能那导值吧。

bhsmr 发表于 2023-11-30 10:26

表单元素设置form的action属性<?php
include_once 'init.php';

if (isset($_POST['sub'])) {

$username = filterstr($_POST['username']);
$password = md5(filterstr($_POST['password']));
$result = $conn->query("select * from users where username='$username' and password='$password'");
if ($result->num_rows > 0) {
   $row = $result->fetch_assoc();
   if ($row['password'] == $password) {
         echo "登录成功";
   } else {
         echo "账号或密码错误";
   }
} else {
   echo "登录失败";
}
exit; // 结束脚本执行，确保只返回登录结果
}

?>
<html>
<head>
<title>管理员登录</title>
<style>
   .login{
         width: 400px;
         margin: 0px auto;
   }
</style>
</head>
<body>
<div class="login">
<form action="login.php" method="POST">
   <table>
         <tr><td><label for="username">用户</label></td><td><input type="text" name="username" id="username"></td></tr>
         <tr><td><label for="password">密码</label></td><td><input type="password" name="password" id="password"></td></tr>
         <tr><td colspan="2"><input type="submit" value="登录" name="sub"></td></tr>
   </table>
</form>
</div>

<script>
function submitForm(event) {
   event.preventDefault(); // 阻止表单默认提交行为

   var form = event.target;
   var formData = new FormData(form);

   var xhr = new XMLHttpRequest();
   xhr.open(form.method, form.action, true);
   xhr.onreadystatechange = function () {
         if (xhr.readyState === XMLHttpRequest.DONE && xhr.status === 200) {
            // 在页面中显示登录结果
            var response = xhr.responseText;
            // TODO: 在页面中显示响应
            console.log(response);
         }
   };
   xhr.send(formData);
}
</script>

</body>
</html>

萌新表示是小白 发表于 2023-11-30 15:53

本帖最后由萌新表示是小白于 2023-11-30 15:54 编辑

<?php
include_once 'init.php';
?>

<html>
<head>
<title>管理员登录</title>
<style>
   .login{
         width: 400px;
         margin: 0px auto;
   }
</style>
</head>
<body>
<?php
if($_POST['sub']){

$username=filterstr($_POST['username']);
$password=md5(filterstr($_POST['password']));
$result=$conn->query("select * from users where username='$username' and password='$password'");
if($result->num_rows>0){
   $row=$result->fetch_assoc();
   if ($row['password']==$password){
         echo "登录成功";
   }else{
         echo "账号或密码错误";
   }
}else{
   echo "登录失败";
}
}
?>
<div class="login">
<form action="login.php" method="POST" style="<?php if($_POST['sub']){ disolay:none} ?>" >
   <table>
         <tr><td><lable for="username">用户</lable></td><td><input type="text" name="username" id="username"></td></tr>
         <tr><td><lable for="password">密码</lable></td><td><input type="password" name="password" id="password"></td></tr>
         <tr><td colspan="2"><input type="submit" value="登录" name="sub"></td></tr>
   </table>
</form>
</div>
</body>
</html>

php的echo打印要写在body里面，method设置为POST，
这里我还帮你添加了个，如果登录了就将登录框隐藏的功能
{:17_1067:}

晚风811 发表于 2023-11-30 17:38

感谢大家,问题已经解决,就是form后面没加method="post",感谢.

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用网页打开php登陆页面不提示登陆是否成功