【python日常学习】猜谜小游戏

aa吴所谓

刚刚学完while语法，瞎编了个猜谜小程序

[Python] 纯文本查看 复制代码

secret_word = "邓超"
guess_tips = ["中国男明星","导演","分手大师"]
guess = ""
guess_count = 0
guess_limit = 3
out_of_guesses = False
i = 0
print("猜测机会共3次！")
while guess != secret_word and not(out_of_guesses):
    if guess_count < guess_limit:
        print(guess_tips[i])
        i +=1
        guess = input("Enter guess:")
        guess_count += 1
    else:
        out_of_guesses = True
if out_of_guesses:
    print("猜测3次机会已用尽，你输了！！")
else:
    print("恭喜你，你猜对了！！")

优化后可以自己输入想要猜的词，提示等，但是目前感觉输入提示词的时候过于麻烦，还在简化

[Python] 纯文本查看 复制代码

secret_word = input("请输入想要对方猜的词：")
guess_tips = eval(input("请输入关键词："))
for a in range(10):
    print("\n")
guess = ""
guess_count = 0
guess_limit = 3
out_of_guesses = False
m = 0
print("猜测机会共3次！")
while guess != secret_word and not(out_of_guesses):
    if guess_count < guess_limit:
        print(guess_tips[m])
        m +=1
        guess = input("Enter guess:")
        guess_count += 1
    else:
        out_of_guesses = True
if out_of_guesses:
    print("猜测3次机会已用尽，你输了！！")
else:
    print("恭喜你，你猜对了！！")

zucker

输入不是汉字，又不报错，这段代码都没。必须要输入汉字或英文的代码，你没写

锋逸520

额，有点迷，前面不管输入了什么，最后一个输入邓超就赢了......

aa吴所谓

锋逸520 发表于 2020-7-29 10:22
额，有点迷，前面不管输入了什么，最后一个输入邓超就赢了......

就是有三次机会猜，每次都会给一个提示词，猜对就赢了，三次都错就输了

FoxBar

来论坛看了这么多帖子，终于找到一个我能看懂的代码了
一起加油

xiao9798

继续加油

wynnshn

学习一下，支持分享