请教，py取嵌套字典里的数值

weeee4

有如下字典（jison）

[Python] 纯文本查看 复制代码

{"result":
{"face_num":1,
"face_list":[{"face_location":{"top":93,"left":275,"width":191,"height":273},"gender":"Male","age":"32"}]
},
"code":"0","message":"success"}

我想取其中的top left width height 数值，应该如何取到，谢谢

yzqhj

[Python] 纯文本查看 复制代码

sd={"result":
{"face_num":1,
"face_list":[{"face_location":{"top":93,"left":275,"width":191,"height":273},"gender":"Male","age":"32"}]
},
"code":"0","message":"success"}
qz=sd['result']['face_list'][0]['face_location']
for i in qz:
    print(qz[i])

yzqhj

挨着找下一级就行了，取到最后的字典，循环取到键，利用键取值

ghd19940802

JSON.result.face_list[0].face_location.top
JSON.result.face_list[0].face_location.left
JSON.result.face_list[0].face_location.width
JSON.result.face_list[0].face_location.height

pixuan

《Python编程：入门到实践》

kang_alone

[Python] 纯文本查看 复制代码

s = {"result":
	     {"face_num": 1,
	      "face_list": [
		      {"face_location": {"top": 93, "left": 275, "width": 191, "height": 273}, "gender": "Male", "age": "32"}]
	      },
     "code": "0", "message": "success"}
print(s["result"]["face_list"][0]["face_location"]["top"])
print(s["result"]["face_list"][0]["face_location"]["left"])
print(s["result"]["face_list"][0]["face_location"]["width"])
print(s["result"]["face_list"][0]["face_location"]["height"])

hhhhpaa

对key取就可以，类似于多维矩阵切片，不过这里矩阵的下标被换成了key

52loli

import json
a = '''{"result":
{"face_num":1,
"face_list":[{"face_location":{"top":93,"left":275,"width":191,"height":273},"gender":"Male","age":"32"}]
},
"code":"0","message":"success"}'''
s = json.loads(a)
s['result']['face_list'][0]['face_location']['top']