python想批量替换，怎么完善下面的代码

ymhld

想把列表里的年月日都换成"-"

[Python] 纯文本查看 复制代码

rrtime = ["1981-11-17 00:00:00", "1980.4.28", "1993.09.16", "1977.4", "","1981年1月"]

for rtime in rrtime:

    for r in ["年","月","日"]:

        rtime=str(rtime).replace(r,"-")

    print (rtime)

    

rrtime = ["1981-11-17 00:00:00", "1980.4.28", "1993.09.16", "1977.4", "","1981年1月"]

for rtime in rrtime:

    rtime=str(rtime).replace(r for r in ["年","月","日"],"-")

    print (rtime)

Megix

Python里面这不是叫列表吗

ymhld

Megix 发表于 2021-3-8 16:11
Python里面这不是叫列表吗

对，一时短路，写成别的了

ymhld

Megix 发表于 2021-3-8 16:11
Python里面这不是叫列表吗

有什么办法？

Megix

ymhld 发表于 2021-3-8 16:20
有什么办法？

能把你想要的最终结果也写在代码的注释里面吗，我不是很懂你要解决什么问题。

pzx521521

for 里面的东西(rtime)不能够修改的, 你可以创建一个新的变量和列表
个人认为转为字符串简单一点, 还少了一个循环

[Asm] 纯文本查看 复制代码

rrtime = ["1981-11-17 00:00:00", "1980.4.28", "1993.09.16", "1977.4", "", "1981年1月"]
str_time = ",".join(rrtime)
for r in ["年", "月", "日", "."]:
    str_time = str(str_time).replace(r, "-")
rrtime = str_time.split(',')
print(rrtime)

lostlq

[Python] 纯文本查看 复制代码

rrtime = ["1981-11-17 00:00:00", "1980.4.28", "1993.09.16", "1977.4", "", "1981年1月"]

for rtime in rrtime:

    for r in ["年", "月", "日", "."]:
        if rtime.endswith(r):
            rtime = str(rtime).replace(r, "")
        else:
            rtime = str(rtime).replace(r, "-")
    print(rtime)

ligxi

[Python] 纯文本查看 复制代码

import re

rrtime = ["1981-11-17 00:00:00", "1980.4.28", "1993.09.16", "1977.4", "", "1981年1月"]
# 需要替换的内容
rec = re.compile(r'[年月日]')
# 不替换多余的-
d1 = list(map(lambda x: rec.sub('-', x), rrtime))
print(d1)
# 替换多余的-
d2 = list(map(lambda y: y[:-1] if y.endswith('-') else y, map(lambda x: rec.sub('-', x), rrtime)))
print(d2)

微凉

6666666666666

ymhld

ligxi 发表于 2021-3-8 17:07
[mw_shl_code=python,true]import re

rrtime = ["1981-11-17 00:00:00", "1980.4.28", "1993.09.16", "1 ...

用rtime=str(rtime).replace(r for r in ["年","月","日"],"-")

即for r in ["年","月","日"]这种方式是实现不了的？