Python enumerate()函数返回类型以及zip()函数类型

十好小学生

[Python] 纯文本查看 复制代码

aList = [1,2,3]

bList = [4,5,6]

cList = [7,8,9]

dList = zip(aList, bList, cList)

for index, value in enumerate(dList):

    print(index, ':', type(value))

输出:
0 : <class 'tuple'>
1 : <class 'tuple'>
2 : <class 'tuple'>
[Finished in 90ms]

[Python] 纯文本查看 复制代码

a= [1,2,3]
print(type(enumerate(a)))
for index, value in enumerate(a):
    print(type(value))

输出:
<class 'enumerate'>
<class 'int'>
<class 'int'>
<class 'int'>
[Finished in 93ms]


问题是第一个例子中为什么会出现元组类型

ryosga

因为 dList 的元素本来就是tuple
>>> x = [1, 2, 3]
>>> y = [4, 5, 6]
>>> zipped = zip(x, y)
>>> zipped
[(1, 4), (2, 5), (3, 6)]

klmatao

aList = [1,2,3]
bList = [4,5,6]
cList = [7,8,9]
# 当你使用zip函数的时候，它会将三个列表最终变成元组
# 对dlist进行遍历打印你就会发现其实d中的元素分别是(1,4,7), (2,5,8),(3,6,9)
dList = zip(aList, bList, cList)
# 你遍历的其实就是上面的三个元组，所以取出来的值还是元组
for index, value in enumerate(dList):
    print(index, ':', type(value))