json问题

weilai911

[Python] 纯文本查看 复制代码

r = '{
	"info": {
		"data": [{
			"activity_icon": "",
			"activity_type": "",
			"avatar": "jpg",
			"cover_url": "72595.jpg",
			"dress": "0",
			"hls_url": "cis60rhb65ed.m3u8",
			"host_intro": "兰博基尼",
			"host_uuid": "cis60rhb65ed",
			"hot": "54603.75",
			"is_follow": "0",
			"location": "1177",
			"nickname": "十二",
			"onlines": "888",
			"rank_icon": "",
			"rtmp_url": "cis60rhb65ed",
			"sex_type": "2",
			"status": "1",
			"stream_id": "cis60rhb65ed",
			"tag": ["歌手"],
			"title": "",
			"tv_room": "0"
		}, {
			"activity_icon": "",
			"activity_type": "",
			"jpg",
			"cover_url": "1636412638728.jpg",
			"dress": "0",
			"hls_url": "dk8tr4qspi9s.m3u8",
			"host_intro": "萌新求关照",
			"host_uuid": "dk8tr4qspi9s",
			"hot": "54445",
			"is_follow": "0",
			"location": "1912",
			"nickname": "神蜜人",
			"onlines": "757",
			"rank_icon": "",
			"rtmp_url": "dk8tr4qspi9s",
			"sex_type": "2",
			"status": "1",
			"stream_id": "dk8tr4qspi9s",
			"tag": ["舞蹈"],
			"title": "",
			"tv_room": "0"
		}],
		"extra": null
	},
	"response_status": "success",
	"msg": ""
}'
s = json.loads(r)
uuid =s['info']['data']['host_uuid']

提示 TypeError: list indices must be integers or slices, not str
只能uuid =s['info']['data'][0]['host_uuid'] 吗

知心

r=直接是字典不行吗，为啥要加个单引号

weilai911

知心 发表于 2022-5-14 21:29
r=直接是字典不行吗，为啥要加个单引号

r 是 requests.get 返回的值 怎么当字典

知心

weilai911 发表于 2022-5-14 21:30
r 是 requests.get 返回的值 怎么当字典

哦哦，你贴出来这部分数据来看的话没有必要么。只能uuid =s['info']['data'][0]['host_uuid'] 吗？是的，data是个列表，列表取值通过索引

weilai911

知心 发表于 2022-5-14 21:33
哦哦，你贴出来这部分数据来看的话没有必要么。只能uuid =s['info']['data'][0]['host_uuid'] 吗？是的， ...

那如何遍历这个列表

surepj

知心 发表于 2022-5-14 21:29
r=直接是字典不行吗，为啥要加个单引号

第28行，只有一个“jpg“，没有键值对？，48行null是个变量吧。
data下是列表，uuid =s['info']['data']['host_uuid']这样也会报错吧

YuanFang0w0

weilai911 发表于 2022-5-14 21:36
那如何遍历这个列表

For循环一下咯

weilai911

surepj 发表于 2022-5-14 21:42
第28行，只有一个“jpg“，没有键值对？，48行null是个变量吧。
data下是列表，uuid =s['info']['data'] ...

跟那个没关系

weilai911

YuanFang0w0 发表于 2022-5-14 21:43
For循环一下咯

我试for

[Python] 纯文本查看 复制代码

i=0
for uuid in uuid:
     i = i+1
    print(uuid)

这样出来的一个一个的单个字母

Semoon

你那个报错,是返回的是个列表字典,需要指定索引号.
比如拿第一个uuid   ,
uuid =s['info']['data'][0]['host_uuid']
用 也可以用lambda加map去遍历直接得到列表
b=list(map(lambda x: x['host_uuid'],s['info']['data']))
print(b)