爬取豆瓣top250的电影排行

一個賬號

我们在在观看一部电影之前，通常会在网上查看评分，而基本上这些评分都是来自于豆瓣，今天我就教大家如何用python爬取豆瓣top250的排名，代码如下：

[Python] 纯文本查看 复制代码

import requests
import bs4
import re

def open_url(url):

    headers = {'user-agent': 'Mozilla/5.0 (Windows NT 10.0; WOW64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/57.0.2987.98 Safari/537.36'}


    res = requests.get(url, headers=headers)

    return res

def find_movies(res):
    soup = bs4.BeautifulSoup(res.text, 'html.parser')
 
    # 电影名
    movies = []
    targets = soup.find_all("div", class_="hd")
    for each in targets:
        movies.append(each.a.span.text)

    # 评分
    ranks = []
    targets = soup.find_all("span", class_="rating_num")
    for each in targets:
        ranks.append(' 评分：%s ' % each.text)

    # 资料
    messages = []
    targets = soup.find_all("div", class_="bd")
    for each in targets:
        try:
            messages.append(each.p.text.split('\n')[1].strip() + each.p.text.split('\n')[2].strip())
        except:
            continue

    result = []
    length = len(movies)
    for i in range(length):
        result.append(movies[i] + ranks[i] + messages[i] + '\n')

    return result

# 找出一共有多少个页面
def find_depth(res):
    soup = bs4.BeautifulSoup(res.text, 'html.parser')
    depth = soup.find('span', class_='next').previous_sibling.previous_sibling.text

    return int(depth)

def main():
    host = "https://movie.douban.com/top250"
    res = open_url(host)
    depth = find_depth(res)

    result = []
    for i in range(depth):
        url = host + '/?start=' + str(25 * i)
        res = open_url(url)
        result.extend(find_movies(res))

    with open("豆瓣TOP250电影.txt", "w", encoding="utf-8") as f:
        for each in result:
            f.write(each)
    
if __name__ == "__main__":
    main()

wangxiaohu104

谢谢楼主分享，学习了

icodeme

测试过了，可以获取到，感谢楼主分享

erui

谢谢楼主分享，学习了

Dipy

实测 有用 辛苦楼主了

lcx4wapj

谢谢分享

大荣

谢谢分享啊

lingweiqiu

谢谢分享

zzqiang97

感谢分享

ly201112

辛苦楼主，之后试试看