[Python] 纯文本查看 复制代码 import pandas as pd
import requests
from bs4 import BeautifulSoup
import re
import logging
from urllib.parse import urljoin
from concurrent.futures import ThreadPoolExecutor, as_completed
from requests.exceptions import RequestException
# 设置日志配置
logging.basicConfig(level=logging.INFO, format='%(asctime)s - %(levelname)s - %(message)s')
column_name = 'Website'
email_column = 'Email'
visited_links = set() # 保存已访问的链接，避免重复访问
def extract_email_from_text(text):
"""从文本中提取邮箱地址，并处理常见的反爬虫技巧"""
email_pattern = re.compile(r'[a-zA-Z0-9._%+-]+@[a-zA-Z0-9.-]+\.[a-zA-Z]{2,}')
text = text.replace('[at]', '@').replace('[dot]', '.').replace('(at)', '@').replace('(dot)', '.')
return email_pattern.findall(text)
def get_all_links(soup, base_url):
"""获取页面中的所有链接，转换为绝对路径"""
links = set()
for link in soup.find_all('a', href=True):
href = link['href']
full_url = urljoin(base_url, href)
if base_url in full_url and full_url not in visited_links:
links.add(full_url)
return links
def find_impressum_link(soup, base_url):
"""查找包含 'Impressum' 或 'Kontakt' 的链接"""
links = soup.find_all('a', href=True)
for link in links:
href = link['href']
if any(keyword in href.lower() for keyword in ['impressum', 'kontakt', 'contact', 'about']):
return urljoin(base_url, href)
return None
def find_email_near_keywords(soup):
"""通过关键字在页面文本中查找邮箱"""
keywords = ['email', 'e-mail', 'contact']
text = soup.get_text().lower()
for keyword in keywords:
if keyword in text:
emails = extract_email_from_text(text)
if emails:
return emails
return None
def get_email_from_url(url, depth=0):
"""从指定 URL 及其链接中提取邮箱地址"""
if url in visited_links or depth > 2: # 限制递归深度
return None
visited_links.add(url)
headers = {
'User-Agent': 'Mozilla/5.0 (Windows NT 10.0; Win64; x64) AppleWebKit/537.36 (KHTML, like Gecko) Chrome/58.0.3029.110 Safari/537.3'
}
try:
response = requests.get(url, headers=headers, timeout=10, verify=False)
if response.status_code == 200:
soup = BeautifulSoup(response.content, 'lxml')
# 1. 先尝试从页面文本中直接提取邮箱
emails = extract_email_from_text(soup.get_text())
if emails:
return emails
# 2. 尝试查找可能的 Impressum 或 Contact 链接
impressum_link = find_impressum_link(soup, url)
if impressum_link:
logging.info(f"找到 Impressum 链接: {impressum_link}")
email = get_email_from_url(impressum_link, depth + 1) # 递归访问 Impressum 链接
if email:
return email
# 3. 在页面中关键字附近查找邮箱
emails = find_email_near_keywords(soup)
if emails:
return emails
# 4. 遍历页面中的所有链接，递归访问这些链接
links = get_all_links(soup, url)
for link in links:
email = get_email_from_url(link, depth + 1)
if email:
return email
except RequestException as e:
logging.error(f"请求 URL 时发生错误: {e}")
return None
def process_url(url):
"""处理单个 URL，提取邮箱地址"""
if pd.notna(url) and url.strip() != '':
url = 'https://' + url.strip()
logging.info(f"访问: {url}")
emails = get_email_from_url(url)
if emails:
email = emails[0] # 如果找到多个邮箱，可以调整为选择最合适的
logging.info(f"找到邮箱: {email}")
return url, email
else:
logging.info("没有找到邮箱")
return url, ''
else:
logging.info(f"跳过空 URL 或无效 URL: {url}")
return url, ''
# 使用上下文管理器来处理 Excel 文件
input_file = 'out3.xlsx'
output_file = 'out3_updated.xlsx'
try:
# 读取 Excel 文件
df = pd.read_excel(input_file, engine='openpyxl')
# 添加邮箱列
if email_column not in df.columns:
df[email_column] = ''
# 使用线程池处理 URL
with ThreadPoolExecutor(max_workers=1000) as executor:
future_to_url = {executor.submit(process_url, row[column_name]): index for index, row in df.iterrows()}
for future in as_completed(future_to_url):
index = future_to_url[future]
try:
url, email = future.result()
df.at[index, email_column] = email
except Exception as e:
logging.error(f"处理 URL 时发生错误: {e}")
# 使用上下文管理器来写入 Excel 文件
with pd.ExcelWriter(output_file, engine='xlsxwriter') as excel_writer:
df.to_excel(excel_writer, index=False)
logging.info(f"处理完成，结果已保存到 {output_file}")
except Exception as e:
logging.error(f"处理 Excel 文件时发生错误: {e}")
写的迷迷糊糊的，勉强能用 | 
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发表于 2024-9-17 15:29
|
发表于 2024-9-18 16:32
|楼主
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