伪代码逻辑求助

hkzxc1991

[C] 纯文本查看 复制代码

int __fastcall main(int argc, const char **argv, const char **envp)
{
  char *v4; // rsi
  char src[8]; // [rsp+10h] [rbp-260h] BYREF
  __int64 v6; // [rsp+18h] [rbp-258h]
  _QWORD v7[2]; // [rsp+20h] [rbp-250h]
  char salt[2]; // [rsp+30h] [rbp-240h] BYREF
  char v9; // [rsp+32h] [rbp-23Eh]
  char v10[8]; // [rsp+40h] [rbp-230h] BYREF
  __int64 v11; // [rsp+48h] [rbp-228h]
  char s[8]; // [rsp+50h] [rbp-220h] BYREF
  __int64 v13; // [rsp+58h] [rbp-218h]
  char v14[256]; // [rsp+60h] [rbp-210h] BYREF
  char dest[8]; // [rsp+160h] [rbp-110h] BYREF
  __int64 v16; // [rsp+168h] [rbp-108h]
  __int64 v17; // [rsp+170h] [rbp-100h]
  __int64 v18; // [rsp+178h] [rbp-F8h]
  _BYTE v19[128]; // [rsp+180h] [rbp-F0h] BYREF
  _DWORD v20[18]; // [rsp+200h] [rbp-70h] BYREF
  char *v21; // [rsp+248h] [rbp-28h]
  int v22; // [rsp+250h] [rbp-20h]
  int v23; // [rsp+254h] [rbp-1Ch]
  __int64 v24; // [rsp+258h] [rbp-18h]
  int v25; // [rsp+260h] [rbp-10h]
  int v26; // [rsp+264h] [rbp-Ch]
  int v27; // [rsp+268h] [rbp-8h]
  int i; // [rsp+26Ch] [rbp-4h]

  v25 = 0;
  v24 = 0LL;
  memset(v20, 0, 0x40uLL);
  memset(v19, 0, sizeof(v19));
  *(_QWORD *)dest = 0LL;
  v16 = 0LL;
  v17 = 0LL;
  v18 = 0LL;
  memset(v14, 0, sizeof(v14));
  i = 0;
  v27 = 0;
  v23 = 0;
  v22 = 0;
  v26 = 0;
  *(_QWORD *)s = 0LL;
  v13 = 0LL;
  *(_QWORD *)v10 = 0LL;
  v11 = 0LL;
  *(_WORD *)salt = 0;
  v9 = 0;
  v7[0] = 0LL;
  v7[1] = 0LL;
  *(_QWORD *)src = 0LL;
  v6 = 0LL;
  v21 = 0LL;

    v21 = (char *)argv[1];
    v23 = strlen(argv[1]);

    strcpy(dest, &v21[v23 - 9]);
    salt[0] = bn_get_salt((unsigned int)(char)v16);
    salt[1] = bn_get_salt((unsigned int)dest[7]);
    v9 = 0;
    v4 = crypt(dest, salt);
    strcpy(s, v4);
    v22 = (char)v16 % 5;
    *((_BYTE *)v7 + v27) = v16;
    v20[v27++] = 0;
    *((_BYTE *)v7 + v27) = bgs((unsigned int)dest[7]);
    v20[v27++] = 1;
    for ( i = 8; 9 - v22 <= i; --i )
    {
    *((_BYTE *)v7 + v27) = bgs((unsigned int)dest[i]);
    v20[v27++] = i;
    }
}

上面是用IDA反编译看到的伪代码，这里有个疑问v16和v22都初始值为0，v22 = (char)v16 % 5;得到的也是0，那么 下面这个循环永远也不会进，这有啥意义呢？是反编译生成的伪代码有问题么？
for ( i = 8; 9 - v22 <= i; --i )
      {
        *((_BYTE *)v7 + v27) = bn_get_sepcial((unsigned int)dest);
        v20[v27++] = i;
      }