批量提取文件

pp67868450

批量按文件夹名称进行提取文件
https://www.picgo.net/image/%7DF ... 40%29U%40DX6.WoQNPl
图中标线的为需要提取的文件，需要保留原目录结构，本层文件夹保留，数据比较多

平淡最真

[Asm] 纯文本查看 复制代码

@echo off
for /f %%a in ('dir /b/ad') do (
	for  %%i in (DR IRI LBI RIFile) do (
	robocopy .\%%a\%%i C:\Users\Admin\Desktop\222\%%a\%%i\ /E
)
)
pause

tantanxin147

黑色蓝柠檬

python可以吗？

pp67868450

黑色蓝柠檬 发表于 2024-11-27 11:38
python可以吗？

展开说说

MQ19781011

以前只提取过文件名称。

黑色蓝柠檬

[Python] 纯文本查看 复制代码

import os
import shutil
import fnmatch
import tkinter as tk
from tkinter import filedialog
def choose_directory():
    
    root = tk.Tk()
    root.withdraw()
    
    directory = filedialog.askdirectory()
    
    return directory
def copy_folders_with_name(root_dir, target_dir, folder_name_pattern):
    
    if not os.path.exists(target_dir):
        os.makedirs(target_dir)
    
    for dirpath, dirnames, filenames in os.walk(root_dir):
        
        for dirname in dirnames:
            for folder_name in folder_name_pattern:
                if fnmatch.fnmatch(dirname, folder_name):
                    
                    source_folder_path = os.path.join(dirpath, dirname)
                    
                    relative_path = os.path.relpath(source_folder_path, root_dir)
                    target_folder_path = os.path.join(target_dir, relative_path)
                    
                    if not os.path.exists(os.path.dirname(target_folder_path)):
                        os.makedirs(os.path.dirname(target_folder_path))
                    
                    shutil.copytree(source_folder_path, target_folder_path)
selected_directory = choose_directory()
print("源文件路径:", selected_directory)
root_directory = selected_directory
selected_directory = choose_directory()
print("提取保存路径:", selected_directory)
target_directory = selected_directory
folder_name_to_copy = ['DR',"IRI","LBI","RIFile"] 
copy_folders_with_name(root_directory, target_directory, folder_name_to_copy)

首先创建你需要保存的新的文件路径，第一次弹窗选择文件夹为你的源文件路径，第二次选择你的创建的新的文件路径，脚本会自动将你所有源文件路径你划线文件名按照源文件目录构成复制到新文件路径。