KeygenMeByLy

Y4Ng

win32汇编写的.
学习win32的窗口和DialogBox

刹话

P个图看看

asd9988

bp exitprocess

Y4Ng

asd9988 发表于 2013-6-12 08:26
bp exitprocess

bp DestroyWindow
bp GetDlgItemTextA

zcc1414

小菜不知道这种类型怎么逆向  求大牛教
为啥  KEYGENME整成了 crackme了········
我只是逆向你的算法  但是不知道逆向出 KEYGENME
eax = ecx*0xC0D + 0x7

[AppleScript] 纯文本查看 复制代码

        int jiamalen = 0x11,zhanghaolen = 0xc;
        int sum1,sum2,sum3,sum4;
        char str[] = "123456789012";
        char str2[] = "12345678901234567";
        char *p = str;
        char *p2 = str2;
 
        __asm
        {
                mov eax,0x2
                add eax,0x6                              ;  11
                add eax,jiamalen
                shl eax,0x6                              ;  19
                lea esi,dword ptr ds:[eax+0x88]          ;  640
                imul eax,esi,0x512                       ;  6C8
                mov sum1,eax
        }


        __asm
        {
                mov edx,sum1
                        mov ecx,0x0
                        jmp jmp2
loop2:
                mov eax,jiamalen
                        sub eax,ecx
                        mov esi,p2
                        xor al,byte ptr ds:[ecx+esi]
                        add edx,eax
                        inc ecx
jmp2:
                cmp ecx,jiamalen
                        jb loop2
                        mov sum3,edx
        }
        __asm
        {
                mov edx,sum3
                        mov ecx,0x0
                        jmp jmp3
loop3:
                mov eax,jiamalen
                        sub eax,ecx
                        mov esi,p2
                        xor al,byte ptr ds:[ecx+esi]
                        add edx,eax
                        inc ecx
jmp3:
                cmp ecx,jiamalen
                        jb loop3
                        mov sum4,edx
        }

        
        __asm
        {
                mov edx,0
                        mov ecx,0x0
                        jmp jmp1
loop1:
                mov eax,zhanghaolen
                        sub eax,ecx
                        mov esi,p
                        xor al,byte ptr ds:[ecx+esi]
                        add edx,eax
                        inc ecx
jmp1:
                cmp ecx,zhanghaolen
                        jb loop1
                        mov sum2,edx
        }

        __asm
        {
                mov eax,sum4
                mov ecx,sum2
                cdq
                idiv ecx
                cmp eax,0xC0D
                jnz exitCUOWU
                cmp edx,0x7
                jnz exitCUOWU
                        mov eax,0x00000000L
                push eax
                        xor ebx,ebx  
                    push ebx  
                        mov byte ptr [esp],0x61   
                        push 0x646e6150
                        mov eax,esp
                        push eax
                        push eax
                        push NULL
                        mov eax,0x77D507EA
                    call  eax 
exitCUOWU:
        }