新出炉的CM，易语言，求大佬指教

CrazyNut

三无产品

密码纯数字 并且 唯一，获取密码算成功 = =

这个爆破太简单了，没啥意思= =

希望能获取算法的大佬给我说下怎么获取的！！！  推算出密码的大佬说一下推算逻辑 谢谢



源码附上就是简单的算法，还有大佬还弄了一个计算器出来

rurg

int sub_40100B()
{
  void *v0; // eax
  void *v1; // eax
  void *v2; // eax
  void *v3; // eax
  void *v4; // eax
  void *v5; // eax
  void *v6; // eax
  void *v7; // eax
  void *v8; // eax
  void *v9; // eax
  void *v10; // eax
  void *v11; // eax
  double v12; // st7
  double v13; // st7
  int result; // eax
  void *v15; // [esp-4h] [ebp-38h]
  int lpMem; // [esp+2Ch] [ebp-8h]
  int lpMema; // [esp+2Ch] [ebp-8h]
  int lpMemb; // [esp+2Ch] [ebp-8h]
  int lpMemc; // [esp+2Ch] [ebp-8h]
  int lpMemd; // [esp+2Ch] [ebp-8h]
  int lpMeme; // [esp+2Ch] [ebp-8h]
  void *lpMem_4; // [esp+30h] [ebp-4h]
  void *lpMem_4a; // [esp+30h] [ebp-4h]
  void *lpMem_4b; // [esp+30h] [ebp-4h]
  void *lpMem_4c; // [esp+30h] [ebp-4h]
  void *lpMem_4d; // [esp+30h] [ebp-4h]
  void *lpMem_4e; // [esp+30h] [ebp-4h]

  v15 = (void *)sub_4015A0(1375797249, 369164290, 8, -1);
  if ( dword_4A65B0 )
    sub_40158E(dword_4A65B0);
  dword_4A65B0 = v15;
  LOBYTE(v0) = (_BYTE)v15;
  if ( !v15 )
    v0 = &unk_481B5C;
  v1 = (void *)sub_40159A(2, (char)v0);
  lpMem_4 = v1;
  if ( !v1 )
    v1 = &unk_481B5C;
  lpMem = sub_40159A(1, (char)v1);
  if ( lpMem_4 )
    sub_40158E(lpMem_4);
  dword_4A65B4 = lpMem;
  LOBYTE(v2) = (_BYTE)dword_4A65B0;
  if ( !dword_4A65B0 )
    v2 = &unk_481B5C;
  v3 = (void *)sub_40159A(3, (char)v2);
  lpMem_4a = v3;
  if ( !v3 )
    v3 = &unk_481B5C;
  lpMema = sub_40159A(1, (char)v3);
  if ( lpMem_4a )
    sub_40158E(lpMem_4a);
  dword_4A65B8 = lpMema;
  LOBYTE(v4) = (_BYTE)dword_4A65B0;
  if ( !dword_4A65B0 )
    v4 = &unk_481B5C;
  v5 = (void *)sub_40159A(3, (char)v4);
  lpMem_4b = v5;
  if ( !v5 )
    v5 = &unk_481B5C;
  lpMemb = sub_40159A(1, (char)v5);
  if ( lpMem_4b )
    sub_40158E(lpMem_4b);
  dword_4A65BC = lpMemb;
  LOBYTE(v6) = (_BYTE)dword_4A65B0;
  if ( !dword_4A65B0 )
    v6 = &unk_481B5C;
  v7 = (void *)sub_40159A(2, (char)v6);
  lpMem_4c = v7;
  if ( !v7 )
    v7 = &unk_481B5C;
  lpMemc = sub_40159A(1, (char)v7);
  if ( lpMem_4c )
    sub_40158E(lpMem_4c);
  dword_4A65C0 = lpMemc;
  LOBYTE(v8) = (_BYTE)dword_4A65B0;
  if ( !dword_4A65B0 )
    v8 = &unk_481B5C;
  v9 = (void *)sub_40159A(3, (char)v8);
  lpMem_4d = v9;
  if ( !v9 )
    v9 = &unk_481B5C;
  lpMemd = sub_40159A(1, (char)v9);
  if ( lpMem_4d )
    sub_40158E(lpMem_4d);
  dword_4A65C4 = lpMemd;
  LOBYTE(v10) = (_BYTE)dword_4A65B0;
  if ( !dword_4A65B0 )
    v10 = &unk_481B5C;
  v11 = (void *)sub_40159A(3, (char)v10);
  lpMem_4e = v11;
  if ( !v11 )
    v11 = &unk_481B5C;
  lpMeme = sub_40159A(1, (char)v11);
  if ( lpMem_4e )
    sub_40158E(lpMem_4e);
  dword_4A65C8 = lpMeme;
  v12 = (double)dword_4A65B4 + (double)dword_4A65B8 * (double)dword_4A65BC + (double)dword_4A65C0 - 82.0;
  if ( v12 < 0.0 )
    v12 = -v12;
  if ( v12 > 0.0000001 )
    return sub_4014AD();
  v13 = (double)dword_4A65C4 + (double)dword_4A65C8 - 108.0;
  if ( v13 < 0.0 )
    v13 = -v13;
  if ( v13 > 0.0000001 )
    result = sub_4014AD();
  else
    result = sub_401405();
  return result;
}

云在天

我说大佬啊，你给个附件也好啊。一张图能看出啥来

CrazyNut

云在天 发表于 2018-4-26 13:23
我说大佬啊，你给个附件也好啊。一张图能看出啥来

刚刚有点bug我重新发= =

旧年白白白

爆破算吗？
00401484  |.  68 751B4800   push CM.00481B75;  密码正确

CrazyNut

旧年白白白 发表于 2018-4-26 15:11
爆破算吗？
00401484  |.  68 751B4800   push CM.00481B75;  密码正确

这个爆破就太没意思了。、。、

旧年白白白

CrazyNut 发表于 2018-4-26 15:16
这个爆破就太没意思了。、。、

哈哈哈  我懒 所以走最快的路

CrazyNut

旧年白白白 发表于 2018-4-26 15:19
哈哈哈  我懒 所以走最快的路

这个爆破没什么难度 0.0   试试获取密码呢

依旧沉沉

云在天 发表于 2018-4-26 13:23
我说大佬啊，你给个附件也好啊。一张图能看出啥来

哈哈，我差点笑出声，竟然云大神也有懵逼的时候

CrazyNut

rurg 发表于 2018-4-26 16:27
int sub_40100B()
{
  void *v0; // eax

大佬这是啥 啊   0.0  怎么搞出来的